Submission #3605000

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Source Code Expand

#include<iostream>
#include<cmath>
using namespace std;
int main()
{
    long long n, k, ans = 1, i = 2;
    cin >> n;
    k = n;
    long long sum = 1;
    for(; i <= sqrt(n); i++){
        if(n % i == 0){
            sum += i;
            if(i != n / i) sum += n / i;
        }
    }
    ans = sum;
    if(ans == n){
        cout << "Perfect" << endl;
    }
    else if(ans > n){
        cout << "Abundant" << endl;
    }
    else{ // ans < n
        cout << "Deficient" << endl;
    }
    return 0;
}

Submission Info

Judge Result